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int[1, 3] 1/(x^3+x) dx
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\[\int\limits_{1}^{3} \frac{1}{(x^{3}+x)} dx\]
partial decomp by chance?
\[\frac{1}{x(x^2+1)}\]
\[\frac{ 1 }{ x } - \frac{ x }{ x^{2}+1 }\]
how would i integrate \[\frac{ x }{ x^{2}+1 }\] ?
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\[\int\limits_{}(1/x) dx=\log(x)\]
Dx[x^2+1] = 2x, so your missing a 2. multiply by 2/2 and borrow it from that
\[\int\limits_{}^{}x/(x ^{2}+1) dx\] put x^2=t 2x dx= dt the integral reduces to
\[(1/2)\int\limits_{}^{}1/(1+t) dt\]
any confusion?/
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yeah partial decomp or long division
ahh, thank you! i should be fine from here on!
you are welcome....!!!!
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