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OpenStudy (anonymous):
ind all solutions in the interval [0, 2π). 2 sin2x = sin x
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OpenStudy (tkhunny):
Double Angle \(\sin(2x) = \)??
OpenStudy (zehanz):
Replace sin2x by 2sinxcosx
OpenStudy (tkhunny):
Gaaaa! ZeHanz gave it away!
OpenStudy (zehanz):
There is still a lot of work left...
OpenStudy (anonymous):
lol
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OpenStudy (anonymous):
Okay then.
OpenStudy (anonymous):
How did you replace it?
OpenStudy (anonymous):
Or is it a fundemental identity?
OpenStudy (zehanz):
It is rather fundamental I'm afraid...
OpenStudy (anonymous):
Oh, okay, thanks.
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OpenStudy (anonymous):
Just simplify by usoing fundemental identities?
OpenStudy (anonymous):
What does it mean by the interval of (0, 2pi)?
OpenStudy (tkhunny):
Why not find ONE, first, before worrynig about that.
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