Question

How would I solve 3x^2+x-=0 by factoring?

I factored it & got (x-1)(3x+4)

My original problem was 3x^2+x=4, but I moved the 4 to the left side.

Answer 1

So you are getting,

(x-1)(3x+4)=0
x=1 and x=-4/3

Now just put them in your orignal question 3x^2+x=4

And check if LHS=RHS then your answer is correct

Answer 2

Oh right! I forgot I have to solve each set of parentheses separately! Okay, well thank you so much:)