Question

HELP!!!!!!!!!!!!!!!!!!! PLEASE!!!!!!!!!!!!!!!!!!!

Use properties of logarithms to solve for x

Answer 1

\[2\log_{2} (2x) + \log_{2}8=6 \]

Answer 2

\[\log_{2} 4x ^{2}+\log_{2} 8=6\]
\[\log_{2} 32x ^{2}=6\]
\[32x ^{2}=2^{6}=64\]
We will get two roots of x. We probably neglect the negative root.