Question

Limit Help
lim as x approches -4
((1/4)+(1/x)/(4+x)

Answer 1

Does that make sense or should i draw it?

Answer 2

\[\huge \lim_{x \rightarrow -4}\frac{\frac{1}{4}+\frac{1}{x}}{4+x}\]
It makes sense c: But I wanted to format it anway, heh.

Answer 3

yes that is it we have only covered limit laws so far.

Answer 4

Ok this one isn't too bad.. it's just to test your silly math skills.

So first let's get a common denominator on top.

Answer 5

My "silly" math skills are slowly coming back I took precalc 5 years ago

Answer 6

Remember how to get a common denominator?
We'll just multiply them both together, that will be the easiest way to do it.
So our common denominator will be 4x.

It looks like the first term is missing an x,
while the second term is missing a 4,

So let's fix that.

\[\huge \lim_{x \rightarrow -4}\frac{\left(\color{cornflowerblue}{\frac{x}{x}}\cdot \frac{1}{4}\right)+\left(\frac{1}{x}\cdot \color{cornflowerblue}{\frac{4}{4}}\right)}{4+x}\]Understand that part ok? :D

Answer 7

\[\huge \lim_{x \rightarrow -4}\frac{\left(\frac{4+x}{4x}\right)}{4+x}\]

Answer 8

okay so now can the denominator of the whole problem cancel out the numerator on the top leaving 4x?

Answer 9

oh well, um let's be careful a sec :)

Answer 10

We can write our problem like this,\[\large \lim_{x \rightarrow -4}\frac{\left(\frac{4+x}{4x}\right)}{4+x} \qquad =\qquad \lim_{x \rightarrow -4} \left(\frac{4+x}{4x}\right)\cdot \frac{1}{4+x}\]

Answer 11

Maybe this will help you see what's going on better.
So what happens when we cancel those out? :O

Answer 12

it is 1/4x so the lim will be -1/16

Answer 13

Yay good job \c:/

Answer 14

thank you!