Question

complete the square
2x^2+8x+1=0

Answer 1

\[2x^2+8x=-1\]
\[x^2+4x=-\frac{1}{2}\]
\[(x+2)^2=-\frac{1}{2}+4=\frac{7}{2}\]
\[x+2=\pm\sqrt{\frac{7}{2}}\] done in one more step