16. What is the equation, in standard form, of a parabola that models the values in the table?
x –2 0 4
f(x) 4 –6 70

A)y = 3x² + 4x – 6
B)y = 4x² + 3x – 6
C)y = 6x² + 3x – 4
D)y = –4x² – 3x + 6

Question

16. What is the equation, in standard form, of a parabola that models the values in the table?
 x –2 0 4
 f(x) 4 –6 70

 A)y = 3x² + 4x – 6
 B)y = 4x² + 3x – 6
 C)y = 6x² + 3x – 4
 D)y = –4x² – 3x + 6

anonymous · Answer

@sh9down45

anonymous · Answer

substitute all  these  value of x  in all the equations and check in which equation u get the corresponding values of y ie f(x) as mentioned in question above.....

anonymous · Answer

what do u mean?

anonymous · Answer

general form of a quadratic equation.
f(x) = ax^2 + bx + c
you have 3 pairs of value for x, f(x). if u substitute them you get a system of 3 equations with 3 unknows. you should be able to solve that.

anonymous · Answer

no I cant I don't know how to do this at all