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Please Help! Triangle Geometry problem.
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im drawing it right now
|dw:1358887429836:dw|
Here's the given info: m<6= a degrees m<1=m<2 m<3=m<4 find m<1, m<3, and m<5 in terms of a
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construct a parallel line |dw:1358887825071:dw|
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Ok...
you can use algebraic way to solve this problem: in FCO you have 180degree - 2 m1( because m1 = m2) = m5 in ICA you have m6 + m4 = m5 or a +m4 = m5 from those above, you have 180 - 2m1 = a + m4 on the other hand, in AFN, you have m1 = 180 - 2 m4 (because m4 = m3) from now, you have 2 equations and 2 variables are m1 and m4.you can solve it to get the solutions and then replace to solve for m5 in term of a Hope this help
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