Question

What is the volume of a solid obtained by rotating the region between the graph of y = (1/2)sin^2 (x^2) and the x-axis for 0 ≤x≤sqrtpi about the y-axis?

Answer 1

The main problem I have is that I can't solve for x.

Answer 2

Are you there?

Answer 3

@jim_thompson5910

Answer 4

Put y =0
0 = (1/2)sin^2 (x^2)
sin^2 (x^2) = 0
sin (x^2) = 0
x^2 =...???

Answer 5

0?

Answer 6

and??

Answer 7

0 is all I can think of.