Question

[√2-(-√2)]^2+(1-0)^2
i always get of 5
when the correct answer is 9

Answer 1

[√2-(-√2)]^2+(1-0)^2

[√2+√2]^2+(1-0)^2

[2√2]^2+(1)^2

4*2+1

9

This means [√2-(-√2)]^2+(1-0)^2 = 9

Answer 2

i see what i did wrong now! thanks!