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[√2-(-√2)]^2+(1-0)^… - QuestionCove
OpenStudy (anonymous):

[√2-(-√2)]^2+(1-0)^2 i always get of 5 when the correct answer is 9

4 years ago
OpenStudy (jim_thompson5910):

[√2-(-√2)]^2+(1-0)^2 [√2+√2]^2+(1-0)^2 [2√2]^2+(1)^2 4*2+1 9 This means [√2-(-√2)]^2+(1-0)^2 = 9

4 years ago
OpenStudy (anonymous):

i see what i did wrong now! thanks!

4 years ago
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