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when solving x^2+4x=-9 what interger or fraction needs to be added to both sides to complete the square
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What is 1/2 the coefficient of the x term?
Using the base y=ax^2+bx+c, In a perfect square trinomial, (b/2)^2 is c
I have done (-6)^2-6(1)(-1)/2(1) but after that I am stuck
x^2+4x=-9 x^2+4x + 4 = -5 (x+2)^2 = -5 I'm not sure what you want to find, so I stop here.
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