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Mathematics 21 Online
OpenStudy (anonymous):

discriminant to determine the type of solutions of the equation

OpenStudy (anonymous):

\[-0.6x ^{2}+2.9x+2.1=0\]

OpenStudy (anonymous):

use \(b^2-4ac\) which in your case is \(2.9^2-4\times 2.1\times (-0.6)\) whatever that is

OpenStudy (anonymous):

since this is pretty clearly a positive number, the equation will have two solutions

OpenStudy (anonymous):

where did you get 2.9^2 from?

OpenStudy (anonymous):

\(ax^2+bx+c=0\) \[-0.6x ^{2}+2.9x+2.1=0\]\[a=-.06,b=2.9,c=2.1\]

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