Question

x2+2x-8=0 solve each equation by the zero factor property

Answer 1

Factor the equation.

Answer 2

\[(x+4)(x-2)=0\]
Then FOIL (First, Outside, Inside, Last) the equation to check that it is correct.
\[(x+4)(x-2)=(x^2+2x-8)\]
Then set each factor equal to zero
\[(x+4)=0\]\[(x-2)=0\]

Solve from there