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(4x+1)^2=20 solve each equation by the square root property
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did you take square root on both sides, first ? what you get ?
solve for X i mean
yeah, take square root on both sides of \((4x+1)^2=20\) what do you get ?
not sure
4x-1=\[\sqrt{20}\] =
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that would be \(4x+1 =\pm \sqrt {20}\) ok? now subtract 1 from both sides, what u get ?
4x=\[\pm \sqrt{20}\] - 1
thats correct, now just divide both sides by 4 and you get 2 values of x.
i got x = PM square root 4
? how ? \(4x=\pm \sqrt{20}-1 \implies x = \dfrac{\pm \sqrt{20}-1}{4}\)
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