Question

5x^2 =20

Answer 1

divide by 5 on both sides of equation

Answer 2

what do you get ? @Nakeisha ?

Answer 3

x^2 -4

Answer 4

you mean

\[x^2=4 ?\]

Answer 5

opps i noticed i post the question wrong it was suppose to be 5x^2-20 not 5x^2=20 sorry

Answer 6

so is the question simplify??

Answer 7

\[x = \sqrt{(20/5)} + e^{i\pi} + e^{2\pi i}\]

Answer 8

o.O

Answer 9

woow ummm

Answer 10

No, actually, this is a very good approach:\[5x^2 = 20 \iff 5x^2 - 20 = 0 \iff 5(x^2 - 4) = 0 \iff x^2 - 4 = 0\]

Answer 11

So simply find the roots of \(x^2 - 4\).

Answer 12

it has to be to factorize completely

Answer 13

do you know how to factorise

\[a^2-b^2 \]

Answer 14

\[a^2-b^2=(a+b)(a-b)\]

Answer 15

use that and get to the result :)

Answer 16

\[x^2 - 4 = x^2 \underbrace{-2x + 2x}_0 - 4\]

Answer 17

\[x^2 - 2x + 2x - 4 = x(x - 2) + 2(x -2) \]

Answer 18

ohhhhhh i see

Answer 19

got it ?

Answer 20

The moment of enlightenment.

Answer 21

:) yh thanks

Answer 22

yw :)