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Find the bearing of the flight from C to A. Can some one please explain how to do this?
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looks like law of sines to me
\[\frac{sinA}{a}=\frac{sinB}{b}=\frac{sinC}{c}\]
thanks
yep, I was trying to see if there was some way to see it is a right triangle; but no luck. we could also use the law of cosine with the given, it just tends to write up scarier but more exact
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