34. An initial population of 295 quail increases at an annual rate of 7%. Write an exponential function to model the quail population. What will the approximate population be after 2 years?
f(x)=(295*0.07)^x :426
f(x)=295(7)^x :14455
f(x)=295(0.07)^x :338
f(x)=295(1.07)^x:338

Question

34.   An initial population of 295 quail increases at an annual rate of 7%. Write an exponential function to model the quail population. What will the approximate population be after 2 years?
f(x)=(295*0.07)^x  :426
f(x)=295(7)^x  :14455
f(x)=295(0.07)^x  :338
f(x)=295(1.07)^x:338

anonymous · Answer

@tyteen4a03   
@campbell_st 
please help me

anonymous · Answer

last option.

anonymous · Answer

$$f(x)=295(1.07)^x$$

anonymous · Answer

295=we use that as a base and consider it as 100%
as it increases by 7% we add that on top of our 100%(initial population of 295)
100%+7%=107% or 1.07 which we get for our brackets and we the population is increasing so we have to times by our original amount and x represents the year which can be 1,2,3,4....
f(x) = 295(1.07)^x