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The point P is on the unit circle. If the y-coordinate of P is -46, and P is in quadrant III , then what does x equal?
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(-4/6)
if the point is on the unit circle then |dw:1358985514434:dw| x^2 + y^2 = 1
you are given y = -4/6. just need to solve for x
then make sure you identify what sign x will have in the context of this problem. for x to be a coordinate in quadrant III, the sign of x will have to be negative.
I got -.754 which would round off to .75, did I do it correctly?
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.745 , sorry!
yes when rounded -0.745 is approximately what the x coordinate is
Thanks a lot! I was over thinking what I had to do.
you did great !
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