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OpenStudy (anonymous):
a machine of 75 percent efficiency is used to lift a load of 103N through a height if 4.8m. How much energy is wasted?
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OpenStudy (anonymous):
didn't I answer this just now? did it got deleted? work done= change in potential energy=mgh=103(4.8)J
OpenStudy (anonymous):
As a first step, ignore the efficiency. How much enery is necessary to lift 103 N for 4.8 m? Once you got that number, figure out how much energy is needed by the engine (using the efficiency) and how much energy is wasted.
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