Question

Find y'. y=2√x- 1/2√x

Answer 1

\[d/dx(x ^{n})=nx ^{n-1}\]

Answer 2

\[\sqrt{x}=x ^{1/2}\]

Answer 3

so now i think u can find the derivative of \[x ^{1/2}\]

Answer 4

?

Answer 5

so would the answer be \[ \frac{ 1 }{ \sqrt{x}\ } + \frac{ 1 }{ 4x \sqrt{x} }\]