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OpenStudy (anonymous):
Please help me solve? I'm not getting it right... x^2+2x+9=0
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OpenStudy (nubeer):
\[x = \frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\] This is the quadratic formula... from your question x^2+2x+9=0 a=1, b = 2,c = 9.. now plug in values u will get 2 values of x
OpenStudy (lacypennelll):
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