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OpenStudy (anonymous):
If vX = 3 meters/second and vY = 4 meters/second, what is the magnitude of the resultant velocity
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OpenStudy (anonymous):
can anyone help me with this?
OpenStudy (anonymous):
sqrt(vx^2+vy^2) = 5 Provided the x and y subscripts you have used denote 2 perpendicular directions
OpenStudy (anonymous):
\[v = \sqrt{Vx^2 + Vy^2}\]
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