Question

Let f(t)=8t2+4t+1 . Find the value of t for which the tangent line to the graph of f(t) has slope 1

Answer 1

do you mean \[f(t)=8t^2+4t+1\] ?

Answer 2

yes

Answer 3

do you know how to find the slope of a tangent line of a function in a point?

Answer 4

do you just use y=mx+b?

Answer 5

you should take derivative to get f'(t) and then let it =1 to solve for t. Hope this help

Answer 6

f'(t) = 16t +4 = 1
---> t = -3/16

Answer 7

thank you!