Question

What is the equation of the hyperbola with foci at (0, ±10) and vertices at (0, ±8)?

Answer 1

center(0,0)vertical transverse axis
a=8
c=10
\[c^2-a^2=b^2\]
b= ___
(y)² /36 - (x)²/ 64 =1
\[\frac{ y^2 }{ b^2 }-\frac{ x^2 }{ c^2 }=1\]
(vertices (0,±a)