Question

A company wants to transmit data over the telephone lines. All their data is transmitted as four-digit integers. write a program that will encrypt their data so that it may be transmitted more securely. Your program should read a four digit number and encrypt as follows: replace each digit by the remainder after the sum of that digit plus 7 is divided by 10. Then swap the first digit with the third, and swap the second digit with the fourth. Then print the encypted integer. Write a seperate program that inputs an encrypted four-digit integer and decrypts it to form the original number

Answer 1

You need to use While Loop too

Answer 2

Here is what i have so far...

#include <iostream>
using namespace std;
int main(){

int num=0;int encrypted_num=0;int digit[3];

cout<< " Input: "
cin>>num;

if (num> 1000 || num<1000){
cout<< "

Answer 3

you might want to use an array to keep the numbers.
and......is the while loop really required?

Answer 4

#include <iostream>
#include <math.h>
using namespace std;
int main()
{
int num[4];
int a,b,c;
cin >>a;
if (a<10000)
{
if(a>1000)
{
for(int i=0; i<4;i++){
b=pow(10, i+1);
num[i]=a%b;
a-=a%b;
if (i>0){
c=pow(10,i);
cout<<num[i];
num[i]/=c;
cout<<"h";
cout<<num[i];
}
}
}
}
else
{
cin.clear();
while (cin.get() != '\n') ;
cout<<"hello";
cin>>a;
}

for(int i=0;i<4;i++){
num[i]+=7;
num[i]=num[i]%10;
}
cout<<num[0];
cout<<num[1];
cout<<num[2];
cout<<num[3];
}

Answer 5

sample code for using a array to keep the numbers for easy reference.
to interchange the values, keep the element in another symbol before assigning it away.

Answer 6

Too late man. I failed

Answer 7

sigh. i guess that's no help then. LOL good luck next time

Answer 8

Hope so