Write the equation of a line that is perpendicular to the given line and that passes through the given point.

y + 2 = 1/3(x – 5); (–4, 3) (1 point)
y = –3x + 15
y = –3x – 9
y = –4x + 3
y = –x – 11

Question

Write the equation of a line that is perpendicular to the given line and that passes through the given point.

y + 2 = 1/3(x – 5); (–4, 3)  (1 point)
y = –3x + 15
y = –3x – 9
y = –4x + 3
y = –x – 11

anonymous · Answer

perpendicular lines of opposite reciprocal slopes. So if the slope is 1/3 then the perpendicular slope would be -3.

Knowing this, c and d CANNOT be correct.

Use this slope and the point given in point slope form

y - y1 = m( x -  x1)

To get the equation