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Given a side length of 18 inches, find the height of a stop sign rounded to the rearest tenth.
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Stop sign is a Regular Octagon. External Angles are 360º/8 = 45º Internal Angles are 180º - 45º = 135º Consider one side, with radii drawn from the center. This creates a 67.5º-67.5º-45º isosceles triangle. Consider the apothem (aka Hieght of the isosceles triangle). \(\tan(67.5º) = \dfrac{Height}{½\cdot 18"}\) Now what? Note: There are likely easier ways. This is just the first thing that popped to mind.
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