Question

Can someone just help me with the steps...
Passing through (3, 3) and perpendicular to y=1/3x + 7

Answer 1

perpendicular tells us
m1 x m2 = -1
m1=gradient of the known equation given, we can see it's 1/3
m2=gradient of the unknown equation which we want to find.
1/3 x m2 = -1
m2 = -3

now use the gradient found m2=3 and the point (3,3) to substitute into the formula to find an unknown equation.
y-y1=m(x-x1)
y-3=-3(x-3)
y=............ (you can do this, I will check it for you)