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x^4 - 4 = 0 How do you solve?
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factorise using a^2-b^2=(a+b)(a-b)
whats A and B? 1 and -4?
x^4 - 4 = 0 (x^2)^2 -2^2=0 (x^2-2)(x^2+2)=0 (x+sqrt(2))(x-sqrt(2))(x+isqrt(2))(x-isqrt(2))=0 hence x=+sqrt(2), -sqrt(2) ,+i*sqrt(2), -i*sqrt(2)
a---> x^2 and b-->2
OHH yeah! thanks, i think i remember now
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