Question

Solve algebraically:
y+5=2x^2 -4x
3x-y=1

Answer 1

put
y=3x-1 in the second equation and then solve the quadratic

Answer 2

2x^2 -4x=3x-1+5
2x^2-7x -4=0
2x^2-8x+x-4=0
2x(x-4) +1(x-4)=0
(2x+1)(x-4)=0
x=-1/2 or x=4

Answer 3

when x=4 y=3(4)-1=11
when x=-1/2 y=3(-1/2) -1=-5/2

Answer 4

i set the two equations equal to each other after getting the y's on one side.... I got -1 and -4 as roots..... ?????

Answer 5

my calculation may not be correct