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OpenStudy (anonymous):
Limit as x->5+ [sqrt(2x-1)-3]/(x-5)
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OpenStudy (anonymous):
use L'Hospital's rule. Take the derivatives of both [sqrt(2x-1)-3] and x-5 and divide them and find the new limes which of 1/sqrt(2x-1), put 5 in there and you get: 1/sqrt(10-1)=1/3
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