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Mathematics 4 Online
OpenStudy (anonymous):

y=4-2x, y=2x^2-3x+1

OpenStudy (anonymous):

then 4-2x=2x^2-3x+1 hence 2x^2-3x+1-4+2x=0 2x^2-x-3=0 solve using formula for quadratic equation(google it if you don't know it) x1,2= -1;3/2 hence y1,2=6;1 so you have two solutions x=-1;y=6 and x=3/2;y=1

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