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Mathematics 13 Online
OpenStudy (anonymous):

In the circle arc BC=75 degrees, Find BCP 105° 150° 37.5° 75°

OpenStudy (anonymous):

OpenStudy (amoodarya):

your problem has lack of information or image is not clear!

OpenStudy (amoodarya):

if pq is tangent line so bcp= 1/2 BC(arc)=1/2(75)=37.5

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