An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.9t^2 +19.6t + 58.8. What is the object's maximum height?
A. 58.8
B. 194.04
C. 78.4
D. 117.6

Question

An object is launched at 19.6 m/s from a height of 58.8 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.9t^2 +19.6t + 58.8. What is the object's maximum height?
	A.	58.8
	B.	194.04
	C.	78.4
	D.	117.6

anonymous · Answer

launched in what direction? upwards or downwards?

abb0t · Answer

Take the first derivative of the function and set it equal to zero.
Solve for t and plug it back in to ur original equation to find max height.

anonymous · Answer

upwards then maximum height means v final =0
$$h'(t)=0$$