Question

Find the average value of the function f on the given interval.

f(x)=1/x^2 on the interval [1,5]

I'll draw what I've got so far.

Answer 1

Take the integral of x^-2 from 1<x<5

Answer 2

What is the next step?

Answer 3

\[\frac{ 1 }{ 4 }\left[ -\frac{ 1 }{ 5 } - \left( -\frac{ 1 }{ 1 } \right) \right]=\]

Answer 4

Thank you that helps me a bunch! So the answer is 1/5 and now I know the

Answer 5

process.

Answer 6

Read up on the fundamental theorem of Calculus II. It explains this clearly.