Question

simplify the expression n^2-n/n^2-3n

Answer 1

\[(n ^{2}-n)/(n ^{2}) -3n?\]

Answer 2

is the 3n in the denominator or no?

Answer 3

its n^2-n / n^2-3n

Answer 4

\[(n ^{2}-n)/(n ^{2}-3n)? OR [(n ^{2}-n)/(n ^{2})] - 3n?\]

Answer 5

1st or 2nd one

Answer 6

first one

Answer 7

Okay if its the first one you can extract "n" from the numerator and the denominator and cancel it. You will be left with (n-1)/(n-3).