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\[f(x)=x ^{2}-8 \ln(x)\] where ln denotes the natural logarithm function. a)found intervals of increase and decrease b) calculates the absolute and relative extremes of the function f c) concavity and convexity
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f'(x) nikalo...
is the problem
f(x)= 2x-8/x then?
set it <0 and >0
hmmm k
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If f'(x)>0 for all x belongs to I , then f is increasing on I. If f'('x)<0 for all belongs to I, then f is decreasing on I.
f(x)= 2x-8/x=0 how can find point
f(x)= 2x-8/x=0 2x-8=x 2x-x-8=0 x-8=0 x=8 is correct??
@Yahoo!
no its not correct...
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i got it
:)
ok
:)
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