PA and PB are tangent to circle O and PD bisects BPA. if mAOC= 68 degrees, how much greater is mBCO than mOAD (the diagram is not to scale).
Could you please explain how you got your answer?
Thank you!

Question

PA and PB are tangent to circle O and PD bisects BPA. if mAOC= 68 degrees, how much greater is mBCO than mOAD (the diagram is not to scale).
Could you please explain how you got your answer?
Thank you!

anonymous · Answer

attachment

anonymous · Answer

mAOC=mBOC=68
OB=OC so mCBO=mBCO=x 
x+x+68=180
2x+68=180   x=56
mAOC+mDOA=180
68+mDOA=180
mDOA=112
OD=OA so mODA=mOAD=y
y+y+112=180
2y+112=180  y=34
mBCO-mOAD=x-y=56-34=22
do you understand??

anonymous · Answer

@marsss Thank you so much! This really helped me.

anonymous · Answer

welcome dude :)