Question

y = x -1 tangent to the graph of f(x) at f'(-3)

Answer 1

I need to find the deriative:
Is f(x) = -3
y = x - 1 so x-(-3) - 1 = -4 so y = 4
x = -3
My point is (-3, -4)
Do I use the point slope equation y - (-4) = -3 (x - 3)
I get y = -3x + 5
How do I find the derivative of f(x) = -3