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Mathematics 9 Online
OpenStudy (anonymous):

Solve: x+y+z=561.5; 3.35y+5.6z=373; 5.6x+2.25y=2769.9; 3.35x+2.25z=1505.66 Pl find x,y and z.

OpenStudy (anonymous):

what grade u in? ahhh this is hard...sorry this isnt much help.

OpenStudy (nottim):

are these al lthe same values for x,y, and z? IS this vectors (i don't remember vectors well)?

OpenStudy (anonymous):

ya

OpenStudy (nottim):

both?

OpenStudy (anonymous):

linear equations

OpenStudy (anonymous):

Make x the subjext for the last equation and y the subject for the second equation. Then sub those into the first equation.

OpenStudy (anonymous):

YOu will get everything in z for the first equation once you do what I told you.

OpenStudy (nottim):

why not rearrange 1 of the equations that has 3 variables, and then substitute in another equation with 2 variables?

OpenStudy (anonymous):

Then you can solve for z and finally you can find y. and then x at the end.

OpenStudy (anonymous):

i tried all equations are coming same

OpenStudy (nottim):

well ,azteck's got this one covered.

OpenStudy (anonymous):

\[3.35x+2.25z=1505.66\] \[3.35x=1505.66-2.25z\] \[x=449.45 -\frac{45}{67}z\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Do the same thing for the second equaiton but in the second equation, make y the subject.

OpenStudy (anonymous):

I got to go somewhere. Toodles. Good luck with that.

OpenStudy (anonymous):

thanks

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