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Complex numbers question
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Show that x=-1 is a root of equation \[x ^{3}+9x^{2}+33x+25 =0\] Hence solve the equation completely
Note: for a cubic equation, either all three roots are real OR one is real and other two roots form a complex conjugate pair
FIRST CASE is simple... -1 is a root of the equation as if we put -1 in above equation ...we get 0
divide the equation by x+1 and tell me what u get???
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