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Mathematics 18 Online
OpenStudy (anonymous):

cos 2 arccos 5 9

geerky42 (geerky42):

Like this? \(\cos 2 \cdot \arccos (5\cdot 9)\)?

OpenStudy (anonymous):

arccos(5/9)

OpenStudy (anonymous):

cos2(arccos(5/9))

geerky42 (geerky42):

cos2(arccos(5/9)) or cos²(arccos(5/9))?

OpenStudy (anonymous):

cos(2arccos(5/9))

geerky42 (geerky42):

HINT: cos(2x) = cos²(x) - sin²(x) = 2cos²(x) - 1

geerky42 (geerky42):

Let x be \(\arccos \left(\dfrac{5}{9}\right)\). Another hint: \( \cos(\arccos(a)) = a \) since cos and arccos is inverse of each other, hence cancel each other out. Does this help you?

geerky42 (geerky42):

?

OpenStudy (anonymous):

they want the exact value

geerky42 (geerky42):

You can get exact value using my hints.

geerky42 (geerky42):

Also, remember that cos²b = cos b cos b = (cos b)²

geerky42 (geerky42):

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