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cos 2 arccos 5 9
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Like this? \(\cos 2 \cdot \arccos (5\cdot 9)\)?
arccos(5/9)
cos2(arccos(5/9))
cos2(arccos(5/9)) or cos²(arccos(5/9))?
cos(2arccos(5/9))
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HINT: cos(2x) = cos²(x) - sin²(x) = 2cos²(x) - 1
Let x be \(\arccos \left(\dfrac{5}{9}\right)\). Another hint: \( \cos(\arccos(a)) = a \) since cos and arccos is inverse of each other, hence cancel each other out. Does this help you?
?
they want the exact value
You can get exact value using my hints.
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Also, remember that cos²b = cos b cos b = (cos b)²
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