Question

Help plz!!!
f(x)=x^2+x-4 and g(x)=x+3
find h(x)=(f o g)(x)

Answer 1

@Aylin

Answer 2

h(x)=(f o g)(x)=f[g(x)]
f[g(x)]=[g(x)]^2+g(x)-4
f[g(x)]=(x+3)^2+x+3-4
f[g(x)]=x^2+6x+9+x+3-4
h(x)=f[g(x)]=x^2+7x+8
do you understand??