Question

Fm(x)=x^3-mx+m-2
Prove that all the curves Intersect at a constant point

Answer 1

you should find derivative.
Fm'(x)=3x^2-m
then it must equal 0
3x^2-m=0 3x^2=m x^2=m/3 x=sqrt(m/3) or x=-sqrt(m/3)
all values of x are constant points.
do you understand??

Answer 2

never understand

Answer 3

Fm(x)=x^3-mx+m-2
=x^3+m(1-x)-2
let x=1 to get f(1)=3
i think that the point constant is A(1.3)

Answer 4

i think you have to study :)

Answer 5

how :) what do you mean

Answer 6

what is this? lol