Question

@mertsj find the center and radius of the given circle. x^2+y^2-8x+12y-8=0

Answer 1

aka complete the square (twice)

Answer 2

you can do this by converting your equation to the form

(x - a)^2 + (y - b)^2 = r^2

where the center is (a,b) and radius = r

you do this by a process called completing the square

Answer 3

ok so I have (x^2-8x)+(y^2+12y)=8

Answer 4

ok now convert x^6 - 8x and y^2 + 12y to the form (x - a)^2 - c

Answer 5

and (y- b)^2 - d

Answer 6

(x^2-8x+16)+(y^2+12y+36)=8+16+36

Answer 7

x^2 - 8x =
(x - 4)^2 - 16

Answer 8

and y^2 + 12y = (y + 6)^2 - 36

Answer 9

so
we get
(x -4)^2 + (y + 6)^2 = 8+16+36 = 60

Answer 10

gotcha

Answer 11

good

Answer 12

compare the above withe standard equation and you'll get what you want