Can someone please show me the rest of the steps to solve this problem?
Write the equation in standard form to find the center and the radius of the circle.

x^2-5=-y^2-6y
+y^2+6y +y^2 +6y
--------------------
x^2-5+y^2+6y=0
+5 +5
--------------------
x^2+y^2+6y=5
(x^2____________) + (y^2+6y+9)=5+9
There's no coefficient for the variable x so I'm not sure what I'm supposed to do with the x^2?

Question

Can someone please show me the rest of the steps to solve this problem?
Write the equation in standard form to find the center and the radius of the circle. 

x^2-5=-y^2-6y
 +y^2+6y +y^2 +6y
--------------------
x^2-5+y^2+6y=0
       +5                 +5
--------------------
x^2+y^2+6y=5
(x^2____________) + (y^2+6y+9)=5+9
There's no coefficient for the variable x so I'm not sure what I'm supposed to do with the x^2?

directrix · Answer

The coefficient of the linear x variable is 0 as in 0*x. Hence, no linear x term appears.

Your work looks good. 

(x^2____________) + (y^2+6y+9)=5+9

(x^2 + 0x + 0 )+ (y^2+6y+9)=5+9
(x + 0) ^2 + ( y + ? )^2 = 14

Finish by writing equation in standard form.
See attached chart if a refresher for standard form is needed.