Question

at the dog park there are several dogs with their owners. countin heads there are 20 , counting legs 62. how many dogs and owners are there?

Answer 1

Let x be the number of owners and let y be the number of dogs.

So for your first equation

x + y = 20

For your second equation

2x + 4y = 62

Write x in terms of y

x = 20 - y

Substitute in the second equation

2(20 - y) + 4y = 62 ===> 40 - 2y + 4y = 62

2y + 40 = 62

2y = 22

y = 11

So there are 11 dogs and 9 owners