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Write the complex number in the form a + bi. 3(cos 270° + i sin 270°)
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What is the cosine of 270?
= 0
What is the sin of 270?
-1
Substitute those values into 3(cos 270° + i sin 270°) and simplify
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i got 3?
3i
*
0+3i in a + bi form
these are my answer choices.. -3i 3i 3 -3
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so would it just be the 3i?
3(0+-1i)=0-3i=-3i
oh yeah duh lol thank you!! can you just tell me if my answer is correct on this other problem?
What other problem?
Find the product of z1 and z2 where z1 = 7(cos 40° + i sin 40°), and z2 = 6(cos 145° + i sin 145°). and for my answer i got .. 42(cos 185° + i sin 185°)
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?
Yes. That is correct.
ok thankyou!!
yw
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