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Evaluate the limits. Use -∞ or ∞ where appropriate. Evaluate lim (x^2-3x+8) as x approaches 2
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lim┬(x→2)〖(x^2- 3x+8)^ 〗
Just plug in 2.
the limit as x approaches 2 is 6.
How did you get 6?
2^2 = 4 4-6 = -2 -2+8=6
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good job.
So is that correct? or was I suppose to factor the equation first?
No, that is correct.
Thanks for the help
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