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Help me please :) question below!!!
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\[\huge\frac{ 3^{2n} \times 25^{2n-1} }{ 15^{n-1} }\]
@Azteck
\[25^{2n-1}=5^{2(2n-1)}\]
\[15^{n-1}=(3\times 5)^{n-1}\]
\[=3^{n-1}\times 5^{n-1}\]
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Now it's just about collecting like terms. \[\frac{ 3^{2n} }{ 3^{n-1} }=?\]
\[\huge3^{n+1}\]?
Yep good.
Do the same for the 5.
\[\huge5^{3n +1}?\]
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And then once you did that, it's 3^n+1 time 5^?
i mean minus one sorry
times*
Not quite. Very close. I'ts 3n-1
ok cool
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thanks
Yeah.
Good job mate.
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