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Mathematics 6 Online
OpenStudy (kuoministers):

Help me please :) question below!!!

OpenStudy (kuoministers):

\[\huge\frac{ 3^{2n} \times 25^{2n-1} }{ 15^{n-1} }\]

OpenStudy (kuoministers):

@Azteck

OpenStudy (anonymous):

\[25^{2n-1}=5^{2(2n-1)}\]

OpenStudy (anonymous):

\[15^{n-1}=(3\times 5)^{n-1}\]

OpenStudy (anonymous):

\[=3^{n-1}\times 5^{n-1}\]

OpenStudy (anonymous):

Now it's just about collecting like terms. \[\frac{ 3^{2n} }{ 3^{n-1} }=?\]

OpenStudy (kuoministers):

\[\huge3^{n+1}\]?

OpenStudy (anonymous):

Yep good.

OpenStudy (anonymous):

Do the same for the 5.

OpenStudy (kuoministers):

\[\huge5^{3n +1}?\]

OpenStudy (anonymous):

And then once you did that, it's 3^n+1 time 5^?

OpenStudy (kuoministers):

i mean minus one sorry

OpenStudy (anonymous):

times*

OpenStudy (anonymous):

Not quite. Very close. I'ts 3n-1

OpenStudy (kuoministers):

ok cool

OpenStudy (kuoministers):

thanks

OpenStudy (anonymous):

Yeah.

OpenStudy (anonymous):

Good job mate.

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